Discussion 12 respond

The request of the classmate posts For their post, choose a chemical reaction equation from the list provided Reaction Equations for practice F21.docx and post your results of the following two tasks. Balance the equation. Chose one of the reactants as the limiting reactant (there may be only one reactant in many cases) Find the mass of one of the products that is produced from that 4.00g of reactant. -for my respond For your follow up posts, respond to another student’s first post by doing the following two tasks. Name the compounds in the reaction equation by the IUPAC system. Identify the reaction as precipitation, double-displacement, acid-base(neutralization), single-displacement, combination, decomposition, or combustion. Some reactions may fit more than one type. I will put two classmate posts below here. So Please read them and respond for that. 1)Discussion 12: H2SO3=H2O+SO2 For my post, I will analyze the balanced reaction H 2 SO 3 → H 2 O + SO 2 1) As stated, the balanced equation is H 2 SO 3 → H 2 O + SO 2 2) Since there is only one reactant ( H 2 SO 3 ) it is the limiting reactant. One mole of the reactant is 82.07g. 4.00 g/82.07g/mol=0.0487 moles. for every mole of H 2 SO 3 reacted, there will be one mole of H 2 O produced. Since we have 0.0487 moles of our reactant we can expect 0.0487 moles of our product H 2 O . H 2 O has a weight of 18.02 g/mol. 0.0487 moles * 18.02 g/mol = 0.878 g of our product H 2 O 2) CaO + H2O -> H2SO4 (#3) Camille Britt posted H2O is the limiting reactant when 4 g of H2O reacts with 12.45 grams of CaO, 16.45 graaqwms of Ca(OH)2 are created .

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